[ENet-discuss] Invalid Conversion in protocol.c

[Nick "Pablo" Pirollo]

I am compiling a project I recently finished and during the build Dev-C++ is complaining about protocol.c converting from enet_uint8 to ENetProtocolCommand on line 114.  For reference the function it is in is reproduced below.

the cuplrit is said to be this line:
commandNumber = outgoingCommand -> command.header.command;

in this function:

static ENetProtocolCommand
enet_protocol_remove_sent_reliable_command (ENetPeer * peer, enet_uint32 reliableSequenceNumber, enet_uint8 channelID)
{
    ENetOutgoingCommand * outgoingCommand;
    ENetListIterator currentCommand;
    ENetProtocolCommand commandNumber;

    for (currentCommand = enet_list_begin (& peer -> sentReliableCommands);
         currentCommand != enet_list_end (& peer -> sentReliableCommands);
         currentCommand = enet_list_next (currentCommand))
    {
       outgoingCommand = (ENetOutgoingCommand *) currentCommand;
        
       if (outgoingCommand -> reliableSequenceNumber == reliableSequenceNumber &&
           outgoingCommand -> command.header.channelID == channelID)
         break;
    }

    if (currentCommand == enet_list_end (& peer -> sentReliableCommands))
      return ENET_PROTOCOL_COMMAND_NONE;

    commandNumber = outgoingCommand -> command.header.command;

    enet_list_remove (& outgoingCommand -> outgoingCommandList);

    if (outgoingCommand -> packet != NULL)
    {
       peer -> reliableDataInTransit -= outgoingCommand -> fragmentLength;

       -- outgoingCommand -> packet -> referenceCount;

       if (outgoingCommand -> packet -> referenceCount == 0)
         enet_packet_destroy (outgoingCommand -> packet);
    }

    enet_free (outgoingCommand);

    if (enet_list_empty (& peer -> sentReliableCommands))
      return commandNumber;
    
    outgoingCommand = (ENetOutgoingCommand *) enet_list_front (& peer -> sentReliableCommands);
    
    peer -> nextTimeout = outgoingCommand -> sentTime + outgoingCommand -> roundTripTimeout;

    return commandNumber;
} 



Thank you in advance for any help you can provide.  If further information is needed, just let me know

Cheers,
Nick
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