std.stdio.writeln should not accept infinite ranges?

[Steven Schveighoffer via Digitalmars-d]

On 11/12/15 10:21 PM, Xinok wrote:
> On Friday, 13 November 2015 at 01:19:22 UTC, Andrei Alexandrescu wrote:
>> On 11/12/2015 08:18 PM, Xinok wrote:
>>> The following code compiles and runs:
>>>
>>> import std.stdio, std.random;
>>>
>>> void main()
>>> {
>>>      writeln(rndGen);
>>> }
>>>
>>> Since rndGen is an infinite range, this code runs forever. It seems to
>>> be that we need to add a check for isInfinite on writeln and other
>>> related functions.
>>>
>>> Does anybody have a use case where this is actually practical? I don't
>>> see a reason for allowing infinite ranges here, considering how easy it
>>> is to write "range.take(n)".
>>
>> Piping a program that produces infinite output into less is practical.
>> -- Andrei
>
> Fair enough. I'm thinking more on the side of safety though and I assume
> that, more often than not, printing an infinite range is unintentional.
> Should it be this easy to shoot ourselves in the foot? I'm not saying it
> should be impossible, but just make it explicit that we intended to
> print an infinite range.

I'm with Andrei on this. It's easy to create infinite loops, this is a 
pitfall of programming. Luckily, your foot will heal from this for next 
time.

-Steve